630-0.00635x^2=0

Solution for 630-0.00635x^2=0 equation:

630-0.00635x^2=0

a = -0.00635; b = 0; c = +630;
Δ = b2-4ac
Δ = 02-4·(-0.00635)·630
Δ = 16.002
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{16.002}}{2*-0.00635}=\frac{0-\sqrt{16.002}}{-0.0127}
=-\frac{\sqrt{}}{-0.0127}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{16.002}}{2*-0.00635}=\frac{0+\sqrt{16.002}}{-0.0127}
=\frac{\sqrt{}}{-0.0127}
$